Optimal. Leaf size=206 \[ \frac{a \sin (e+f x) \cos (e+f x) \cos ^2(e+f x)^{\frac{1}{2} (n p-1)} \left (c (d \sec (e+f x))^p\right )^n F_1\left (\frac{1}{2};\frac{1}{2} (n p-1),1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )}-\frac{b \sin (e+f x) \cos ^2(e+f x)^{\frac{n p}{2}} \left (c (d \sec (e+f x))^p\right )^n F_1\left (\frac{1}{2};\frac{n p}{2},1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )} \]
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Rubi [A] time = 0.402304, antiderivative size = 206, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {3948, 3869, 2823, 3189, 429} \[ \frac{a \sin (e+f x) \cos (e+f x) \cos ^2(e+f x)^{\frac{1}{2} (n p-1)} \left (c (d \sec (e+f x))^p\right )^n F_1\left (\frac{1}{2};\frac{1}{2} (n p-1),1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )}-\frac{b \sin (e+f x) \cos ^2(e+f x)^{\frac{n p}{2}} \left (c (d \sec (e+f x))^p\right )^n F_1\left (\frac{1}{2};\frac{n p}{2},1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )} \]
Antiderivative was successfully verified.
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Rule 3948
Rule 3869
Rule 2823
Rule 3189
Rule 429
Rubi steps
\begin{align*} \int \frac{\left (c (d \sec (e+f x))^p\right )^n}{a+b \sec (e+f x)} \, dx &=\left ((d \sec (e+f x))^{-n p} \left (c (d \sec (e+f x))^p\right )^n\right ) \int \frac{(d \sec (e+f x))^{n p}}{a+b \sec (e+f x)} \, dx\\ &=\left (\cos ^{n p}(e+f x) \left (c (d \sec (e+f x))^p\right )^n\right ) \int \frac{\cos ^{1-n p}(e+f x)}{b+a \cos (e+f x)} \, dx\\ &=-\left (\left (a \cos ^{n p}(e+f x) \left (c (d \sec (e+f x))^p\right )^n\right ) \int \frac{\cos ^{2-n p}(e+f x)}{b^2-a^2 \cos ^2(e+f x)} \, dx\right )+\left (b \cos ^{n p}(e+f x) \left (c (d \sec (e+f x))^p\right )^n\right ) \int \frac{\cos ^{1-n p}(e+f x)}{b^2-a^2 \cos ^2(e+f x)} \, dx\\ &=\frac{\left (b \cos ^2(e+f x)^{\frac{n p}{2}} \left (c (d \sec (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^{-\frac{n p}{2}}}{-a^2+b^2+a^2 x^2} \, dx,x,\sin (e+f x)\right )}{f}-\frac{\left (a \cos ^{n p+2 \left (\frac{1}{2}-\frac{n p}{2}\right )}(e+f x) \cos ^2(e+f x)^{-\frac{1}{2}+\frac{n p}{2}} \left (c (d \sec (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^{\frac{1}{2} (1-n p)}}{-a^2+b^2+a^2 x^2} \, dx,x,\sin (e+f x)\right )}{f}\\ &=-\frac{b F_1\left (\frac{1}{2};\frac{n p}{2},1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos ^2(e+f x)^{\frac{n p}{2}} \left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{\left (a^2-b^2\right ) f}+\frac{a F_1\left (\frac{1}{2};\frac{1}{2} (-1+n p),1;\frac{3}{2};\sin ^2(e+f x),\frac{a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos (e+f x) \cos ^2(e+f x)^{\frac{1}{2} (-1+n p)} \left (c (d \sec (e+f x))^p\right )^n \sin (e+f x)}{\left (a^2-b^2\right ) f}\\ \end{align*}
Mathematica [B] time = 25.5924, size = 5411, normalized size = 26.27 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.147, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( c \left ( d\sec \left ( fx+e \right ) \right ) ^{p} \right ) ^{n}}{a+b\sec \left ( fx+e \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (d \sec \left (f x + e\right )\right )^{p} c\right )^{n}}{b \sec \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (\left (d \sec \left (f x + e\right )\right )^{p} c\right )^{n}}{b \sec \left (f x + e\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \left (d \sec{\left (e + f x \right )}\right )^{p}\right )^{n}}{a + b \sec{\left (e + f x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (d \sec \left (f x + e\right )\right )^{p} c\right )^{n}}{b \sec \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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